CLASS 11 · CHAPTER 1 · MEASUREMENT
Units and Measurements
Every physics answer is a number attached to a unit, measured with an instrument that has its own limits. This chapter is about respecting those limits, not just quoting formulas.
Watch it happen
Now suppose this particular caliper has a zero error:
Corrected length = observed reading − zero error = 4.35 cm − 0.00 cm = 4.35 cm
Drag the slider and watch which vernier line lines up with a main scale line. That single coincidence is the entire instrument: once you can read it, the “formula” below is just describing what your eyes already found.
Where the formula comes from
A standard vernier caliper divides its sliding scale into parts that together span 9 main scale divisions (MSD), so that:
The least count is just the gap this creates between one main scale division and one vernier division:
Dimensional analysis uses the same kind of matching. To find how the time period of a simple pendulum depends on its length and gravity , assume a power-law form and match dimensions on both sides:
Matching powers of gives , so ; matching powers of gives , so :
Where the shortcut stops working
That last derivation found the shape of the pendulum formula, the square root, the ratio of to , but it could not find the constant . Dimensional analysis can never recover a pure number, because a pure number has no dimensions to match against. It’s why every dimensionally-derived formula in this course carries an unknown constant that has to come from somewhere else, usually a full derivation or an experiment.
The method has sharper limits too. It cannot handle a quantity that depends on the sum of two differently-scaled terms, like : both terms already have the same dimension, so dimensional analysis alone could never have told you there should be a in front of the second one, or even that the equation has two terms rather than one. And it breaks down completely for any relation built from a trigonometric, exponential, or logarithmic function, because the argument of or has to be dimensionless in the first place, which dimensional analysis simply assumes rather than proves.
Apply it under exam conditions
Q1. A vernier caliper with a least count of 0.01 cm has a main scale reading of 3.4 cm, with the 6th vernier division coinciding. The caliper has a zero error of +0.03 cm. Find the true length.
Q2. Check whether is dimensionally consistent.
Every term must reduce to : , and . All three terms match, so the equation is dimensionally consistent, though (as above) that alone doesn’t prove the factor of is correct.
Quick answers
What is least count?+
The smallest change in a quantity that a given instrument can actually detect. For a standard vernier caliper it's 0.01 cm, set entirely by how finely the vernier scale is divided against the main scale.
Why does a zero error need to be subtracted, not added?+
It depends on the sign. A positive zero error means the instrument over-reads, so you subtract it; a negative zero error means it under-reads, so subtracting a negative number effectively adds the missing length back. One rule, corrected = observed − zero error, handles both once the sign is right.
Can dimensional analysis prove a formula is correct?+
No, only that it isn't obviously wrong. It can never recover a pure numerical constant, and it can't distinguish between two dimensionally identical but physically different formulas.
What's the difference between accuracy and precision?+
Accuracy is how close a measurement is to the true value; precision is how consistent repeated measurements are with each other. An instrument can be very precise while still being consistently wrong, which is inaccurate.
Why do significant figures matter?+
Because they honestly report how well you actually know a number. Writing more digits than your instrument can justify claims a precision the measurement doesn't have.
Related concepts
Physics doesn’t stay inside chapter boundaries. Neither should you.
