Physics by Lamhi: Not Your Boring Physics

CLASS 12 · CHAPTER 5 · MAGNETISM

Magnetism and Matter

A compass needle always settles pointing north, never south, even though both directions are places where the magnetic torque on it is exactly zero. Rotate the bar magnet below and find out why only one of those zeros ever actually holds.

01 · See it

Watch it happen

The torque here is pulling the magnet the rest of the way toward θ = 0°, where it will eventually settle.

45°
Angle θ
0.0707 N·m
Torque τ
-0.0707 J
Potential energy U
—
Equilibrium?

Drag θ from 0° up to 180°. Torque climbs from zero, peaks at 90°, then falls back to zero again at 180°, the same value it had at the start. But the equilibrium readout flips from Stable to Unstable between those two zeros: the torque curve alone can’t tell you which is which, you have to look at how potential energy U behaves right around each point.

02 · Derive it

Where the formula comes from

A bar magnet behaves, from the outside, just like a current-carrying solenoid, the equivalent solenoid picture. A solenoid of NN turns, each carrying current II and enclosing area AA, has a magnetic dipole moment:

Dipole moment of a current loop/solenoid
M=NIA\textcolor{#e08a1e}{M} = NIA

A bar magnet is assigned the same quantity MM, pointing from its south pole to its north pole, precisely because it produces the same external field pattern and obeys the same torque law as that equivalent solenoid.

Placed in a uniform external field BB at angle θ\theta to MM, the two forces on the (equal and opposite) poles form a couple. Each force has magnitude qBqB (pole strength times field), separated by a perpendicular lever arm 2asin⁡θ2a\sin\theta, giving:

Torque on a dipole
τ=MBsin⁡θ\textcolor{#e08a1e}{\tau} = MB\sin\theta

Potential energy is defined by the work needed to rotate the dipole from a reference angle (conventionally 90°90°, where U=0U=0) to angle θ\theta, which integrates the torque above:

Potential energy of a dipole
U=−MBcos⁡θ\textcolor{#e08a1e}{U} = -MB\cos\theta

With this sign convention, UU is lowest (most negative) when MM and BB point the same way, exactly where the simulation above reads Stable.

03 · Break it

Where the shortcut stops working

Both θ=0°\theta=0° and θ=180°\theta=180° give sin⁡θ=0\sin\theta=0, so τ=MBsin⁡θ=0\tau=MB\sin\theta=0 at both. It’s tempting to read “zero torque” as “nothing is happening here, so it must just sit still”, and treat the two positions as interchangeable. They are not. Zero torque only describes this exact instant; it says nothing about what happens the moment something disturbs the angle even slightly, which, in the real world, something always does.

To tell the two apart, look at potential energy, not torque, just either side of each point. Near θ=0°\theta=0°, U=−MBcos⁡θU=-MB\cos\theta is at a minimum, nudge θ\theta a little either way and UU rises, meaning the system has to do work to move away from there. A restoring torque appears the instant you leave θ=0°\theta=0°, and it always points back toward it. That is exactly what a stable equilibrium means.

Near θ=180°\theta=180°, UU is at a maximum instead. Nudge θ\theta slightly away from 180° and UU falls, the dipole can lower its energy by continuing to rotate away, not by returning. The torque that appears doesn’t restore θ=180°\theta=180°, it accelerates the dipole away from it, all the way around to θ=0°\theta=0°, never back to 180°180°. That is an unstable equilibrium: a true zero-torque point that no real disturbance leaves alone.

This is precisely why a compass needle always settles pointing to magnetic north and never to magnetic south, even though “pointing south” is also, momentarily, a position of zero torque. The rule to remember: zero torque is necessary for equilibrium, but you must check whether UU sits at a minimum (stable) or a maximum (unstable) before calling it one.

04 · Master it

Apply it under exam conditions

Q1. A bar magnet of dipole moment 0.8 A·m² is placed at 30° to a uniform field of 0.5 T. Find the torque on it.

τ=MBsin⁡θ=(0.8)(0.5)sin⁡30°=(0.4)(0.5)=0.2 N⋅m\tau = MB\sin\theta = (0.8)(0.5)\sin 30° = (0.4)(0.5) = \textcolor{#e08a1e}{0.2\text{ N·m}}

Q2. A dipole sits at θ = 2° in one experiment and θ = 178° in another, both in the same uniform field. Both report a torque reading close to zero. Which one is in a stable equilibrium, and why?

θ = 2° is close to θ = 0°, where U=−MBcos⁡θU=-MB\cos\theta is at its minimum: any further nudge raises UU, so a restoring torque pulls it back toward 0°. This is the stable one.

θ = 178° is close to θ = 180°, where UU is at its maximum: any further nudge lowers UU, so the torque pushes it further away, around to 0°, not back to 180°. This one is unstable, despite reading almost the same (near-zero) torque as the first.

05 · FAQs

Quick answers

If torque is zero at both θ = 0° and θ = 180°, how can one be stable and the other not?+

Zero torque only means the magnet isn't being pushed to rotate right now, it says nothing about what happens if it's nudged. At θ = 0°, a small nudge creates a restoring torque that pushes the magnet back, U is at a minimum there, so it's stable. At θ = 180°, a small nudge creates a torque that grows, pushing it further away, U is at a maximum there, so it's unstable. Zero torque is necessary for equilibrium but doesn't by itself tell you whether that equilibrium holds.

Why doesn't a compass needle ever settle pointing toward magnetic south?+

It technically could, in principle, if it were placed exactly at θ = 180° with zero disturbance, since torque really is zero there. But θ = 180° is unstable: any real nudge, air currents, friction in the pivot, Earth's field not being perfectly uniform, grows instead of fading, and the needle swings all the way around to θ = 0° (pointing north), never back to south. That's the same reason a pencil balanced exactly on its tip falls, a perfect equilibrium that no real-world perturbation leaves alone.

Is the magnetic dipole moment M the same as the magnetic field B?+

No. M (unit A·m²) is a property of the magnet itself, how strong a 'magnetic dipole' it is, built from its loop current and area (or its pole strength and length). B (unit T) is the external field the magnet sits in, produced by some other source (a solenoid, the Earth, another magnet). Torque and potential energy both depend on the product of the two, τ = MB sin θ and U = −MB cos θ, but doubling M and doubling B have completely different physical meanings.

Why is a bar magnet treated as 'equivalent' to a current-carrying solenoid?+

Because, from outside, their magnetic fields look the same: both produce a dipole-like field with a north-seeking and south-seeking end, and both experience the identical torque and potential-energy laws in an external field. This equivalence is what justifies defining a bar magnet's dipole moment the same way as a loop's, M = NIA for the solenoid, and treating the bar magnet as 'built from' amperian current loops rather than from any actual magnetic charge.